Battle of Sullivan's Island

The Battle of Sullivan's Island on June 28, 1776 was one of the most important American victories of the war's early phase, protecting Charleston and the entire southern seaboard from British conquest for three critical years. The British operation involved nine warships and 2,900 troops under Commodore Peter Parker and General Henry Clinton, intended to seize Charleston as a southern base.

Colonel William Moultrie commanded 435 South Carolina Continentals in an unfinished fort built of palmetto logs filled with sand — a material the British dismissed as useless for defense. General Charles Lee thought the fort a 'slaughter pen' and considered ordering evacuation. Moultrie refused. The battle began at 11 AM when Parker's fleet opened furious bombardment. The spongy palmetto logs, instead of splintering when struck by cannon balls, simply absorbed the impact. Moultrie's gunners, though short on powder, fired with deliberate accuracy — dismounting British cannon, shattering the flagship's cabin, wounding Parker himself, and killing and wounding hundreds of sailors.

Three British frigates attempting flanking positions ran aground on shoals and came under devastating fire. One had to be burned by its crew. A British infantry attempt to wade across a shoal to flank the fort was repulsed by accurate American rifle fire. After ten hours of bombardment, Parker's battered fleet withdrew having accomplished nothing. American casualties were remarkably light — twelve killed and twenty-five wounded.

The battle earned the palmetto tree its place on the South Carolina state flag, where it remains today as a symbol of resilience. It delayed British operations in the South for over three years, giving the Patriots time to build their defenses. The victory was celebrated throughout the colonies and remains one of the most significant early American successes of the war.